draw line in a picture
125 次查看(过去 30 天)
显示 更早的评论
Hello guys does anyone know how can i draw a line in a picture.
For example i want to draw a 45 degree red line in the next picture starting from the top left corner of the picture and ending n the other end of the picture.
0 个评论
采纳的回答
Walter Roberson
2021-3-26
编辑:Walter Roberson
2021-4-4
img = imread('https://www.mathworks.com/matlabcentral/answers/uploaded_files/562881/image.jpeg');
sz = size(img);
endx = min(sz(1), sz(2));
h(1) = image(img);
hold on
h(2) = plot([1 endx], [1 endx], 'r');
hold off
Or if you need the line "burned in" to the image:
img = imread('https://www.mathworks.com/matlabcentral/answers/uploaded_files/562881/image.jpeg');
sz = size(img);
endx = min(sz(1), sz(2));
nimg = insertShape(img, 'Line', [1 1 endx endx], 'Color', 'r');
h(1) = image(nimg);
The difference between these two is that in the first version, the red line is only visible in what is drawn, with it not being made part of the image array; h will end up as a vector containing the handle to the image display object that only knows about the gray scale image, and a handle to the line display object. In the second version, the red line is part of the array stored in nimg, suitable for further processing (or writing to a file), and h will be the handle of the image display object that only knows about displaying the array that inherently has the red line as part of the data.
11 个评论
Walter Roberson
2021-4-4
I corrected the insertShape call,
nimg = insertShape(nimg, 'Line', [0 0 endx endy], 'Color', line_cols{k});
更多回答(1 个)
MG
2021-3-26
Would this work for you:
hold on
ax=axis;
x = ax(1:2);
y = ax([3 4]); %might want to change cordinates (check with 'axis on')
line(x,y,'Color','red','LineStyle','-')
4 个评论
Walter Roberson
2021-3-26
编辑:Walter Roberson
2021-3-26
In my code, the approaches do not change if you use imshow() instead of image()
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Data Distribution Plots 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!