Finding distance from a projectile.
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What is each line is doing on this code?
D=[1 xi(end);1 newx];
b=[yi(end);newy];
a=D\b
Distance = (-a(1)/a(2))
newx = Distance;
newy = 0;
b=[ui(end);newu];
a=D\b;
u2 = (a(1)+a(2)*Distance);
newu = u2;
b=[vi(end);newv];
a=D\b;
v2 = (a(1)+a(2)*Distance);
newv = v2;
newv = -(newv*COR);
回答（1 个）
Adam Danz
2021-3-29
0 个投票
Much of this is basic Matlab syntax that should be understood in order to do almost anything in Matlab. Take some time to go through the Matlab Onramp to get caught up.
xi(end) is indexing the variable xi, retrieving is end or last value.
D=[1 xi(end);1 newx] is creating a 2x2 matrix.
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2021-3-29
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