Creating an algorithm for a Simultaneous Equation
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3000x + 1000y = 35000 (1)
240x + 5y = 1665 (2)
Please can you help me create an algorithm that will keep increasing the value of 3000 by 20% (i.e 3000 + 20%*3000) and at the same time giving the corresponding results of "x" and "y".
Thank you in anticipation.
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David Hill
2021-3-31
k=3000*(.2).^(0:10);%however long you want
for j=1:length(k)
A=[k(j) 1000;240 5];
b=[35000;1665];
out(j,:)=A\b;
end
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