Sequentially load images and generates textures with corresponding names

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Yu Takahashi
Yu Takahashi 2021-4-1
评论： Yu Takahashi 2021-4-2
Dear community members
My plan is to present images that is named sequentially (i.e., A_01.jpg, A_02.jpg...) on the screen using psychtoolbox functions.
I was stock at the very first step of generating the corresponding textures using the images that are all systematically named A_X.jpg. (X = 1:40) .
( p.s. all images were stored in the same folder)
The script currently looks something like this: (obviously this is very ineffecient)
imageA01 = imread('A_01.jpg,'); % read the image
A01_texture = Screen('Maketexture', windowPtr,imageA01); % generate and neme the texture
% Screen('Maketexture', windowPtr,imageA02) is a psychtoolbox function
% that generate textures that could be "flipped"(i.e., presented on
% the screen) upon screen refreshes
imageA02 = imread('A_02.jpg,');
A02_texture = Screen('Maketexture', windowPtr,imageA02);
imageA03 = imread('A_03.jpg,');
A03_texture = Screen('Maketexture', windowPtr,imageA03);
...
imageA40 = imread('A_40.jpg,');
A40_texture = Screen('Maketexture', windowPtr,imageA40);
I've tried to simplify this using a for loop, but faild to dynamically create and name the individual textures.
Also saw this:
https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval
which explicitely stated that we should NOT dynamically name variables, so I was't sure what to do.
Any help or comment is appreciated, thanks in advance.

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采纳的回答

David Hill
David Hill 2021-4-1
Why not use cell array?
for k=1:40
s=num2str(k);
if length(s)==1
s=['0',s];
end
texture{k}=Screen('Maketexture', windowPtr,imread(sprintf('A_%s.jpg',s));
end
  2 个评论
Yu Takahashi
Yu Takahashi 2021-4-2
for k=1:40
s=num2str(k);
if length(s)==1
s=['0',s];
end
texture{k}=Screen('Maketexture', windowPtr,imread(sprintf('A_%s.jpg',s)));
% one missing parentheses at the very end
end

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