Solving a simple equation

1 次查看（过去 30 天）
Richard Golem
Richard Golem 2021-4-2
评论： Paul Hoffrichter 2021-4-5
%Angle = B
%Thickness = u
%Inner Radius = p
%Developed length = L
%L = L1+L2+a
%Bend Allowance = a
B = 90;
u = .075;
p = .046875;
L1 = 12;
L2 = 3.5;
syms B u p v;
v = solve(v == pi*((180-B)/180)*(p+(u/2e-6)*(6.5e-6+5e-6*log(p/u)))-2e-6*(p+u),v);
%syms v L1 L2 L;
%L = solve(L==L1+L2+v);
disp(v)
%I am trying to ultimatly solve for L, however when I try and solve for v it comes out wit a really long and complicated equation that includes my variables. I put the equation with the right number in my calculator and got a single number using the same notation, so I'm pretty sure the problem is somewhere in my code. It is probalby really obvius, but I am pretty new and don't know what I'm doing wrong. Any help would be great, thank you.

请先登录，再回答此问题。

采纳的回答

Paul Hoffrichter
Paul Hoffrichter 2021-4-2
Sorry, no idea if this is right.
clc, clearvars
%Angle = B
%Thickness = u
%Inner Radius = p
%Developed length = L
%L = L1+L2+a
%Bend Allowance = a
B = 90;
u = .075;
p = .046875;
L1 = 12;
L2 = 3.5;
% % % syms B u p v;
syms v
v = solve(v == pi*((180-B)/180)*(p+(u/2e-6)*(6.5e-6+5e-6*log(p/u)))-2e-6*(p+u),v);
%syms v L1 L2 L;
%L = solve(L==L1+L2+v);
disp(v)
val = double(v);
disp(val);
Output:
1432527233130751/4503599627370496
0.318084943524866

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Programming 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by