How to write for loop for an array calculation ?
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I am trying to use below code to calculate and write into new variable but it's taking last value and giving same whole vector.
for k=1:3
for j = 22:24
%three values expected and write into A
A(k,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
end
end
output:
A = [0.5;0.5;0.5]
5 个评论
Mathieu NOE
2021-4-2
hello
sure , you are doing 3 times the same operation, so it is no surprise that A contains always the same value.
what is the intention ? why the 2 loops ?
Sajid Afaque
2021-4-2
if i understood correctly then,
it is because your inner loop runs over j several times for each k value
hence in A the k position which you have given is overwritter for each j.
count = 1;
for k=1:3
for j = 22:24
%three values expected and write into A
A(count,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
count = count+1;
end
end
if this doesnt solves your query then please do explain your problem in other way as is it difficult to understand your current description of problem
Jeevan Kumar Bodaballa
2021-4-2
Sajid Afaque
2021-4-2
编辑：Sajid Afaque
2021-4-2
Great that it worked. @Jeevan Kumar Bodaballa
if my comment helped you then please accept my answer, as my previous answer was in comment section
采纳的回答
Sajid Afaque
2021-4-2
if i understood correctly then,
it is because your inner loop runs over j several times for each k value
hence in A the k position which you have given is overwritter for each j.
count = 1;
for k=1:3
for j = 22:24
%three values expected and write into A
A(count,:) = (f1_lh_nwaer(j,25)+f1_lh_nwaer(j+1,25))/2;
count = count+1;
end
end
if this doesnt solves your query then please do explain your problem in other way as is it difficult to understand your current description of problem
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