Need help with "mirroring" function
显示 更早的评论
This is my code so far:
t=0:(20000/723/.05) % (20000/723/.05) represents the value of t when theta = 0
x= .05*t
theta = acos(.0723*x / 2)
plot(t, theta)
My goal is to take the plot of the function on this t interval and mirror it across t = 20000/723/.05. Then I want to mirror this mirrored image across t = 40000/723/.05, then mirror that mirrored image across t = 60000/723/.05, and so on. Not sure if this makes sense, so my drawing below shows what I have in blue, and what I want to add in red.
Essentially, as t goes to some number (finite, but I don't know what yet) I want the plot to keep mirroring. Does anyone know how I could do this?
1 个评论
William Rose
2021-4-2
This works:
>> x=0:.01:1;
>> y=log(1+x);
>> plot([x,x(end)+x,2*x(end)+x,3*x(end)+x],[y,flip(y),y,flip(y)]);
See output plot.
采纳的回答
William Rose
2021-4-2
1 个投票
Using your equations and ranges, you would do:
>> x= .05*(0:(20000/723/.05));
>> theta = acos(.0723*x / 2);
>> plot([t,t(end)+t,2*t(end)+t,3*t(end)+t],[theta,flip(theta),theta,flip(theta)])
which produces the plot below. Extend it as much as you wish.
3 个评论
William Rose
2021-4-3
My previous answer plotted x vs θ, but you wanted t versus θ. Therefore do
>> t=0:553;
>> te=t(end);
>> theta=acos(1.8075e-3*t);
>> plot([t,te+t,2*te+t,3*te+t,4*te+t],[theta,flip(theta),theta,flip(theta),theta]);
I added another segment to the plot, I got rid of x, which was not needed, and I simplified the fractions. As you can see, the hoizontal axis is now t, not x.
Rosemaryl21
2021-4-3
编辑：Rosemaryl21
2021-4-3
William Rose
2021-4-4
更多回答（1 个）
William Rose
2021-4-2
0 个投票
This works:
>> x=0:.01:1;
>> y=log(1+x);
>> plot([x,x(end)+x,2*x(end)+x,3*x(end)+x],[y,flip(y),y,flip(y)]);
See output plot.
类别
在 帮助中心 和 File Exchange 中查找有关 Introduction to Installation and Licensing 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
