Coder Size Mismatch error

Question

Naga Manoj Kumar Lakkoju 2021-4-3

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/791634-coder-size-mismatch-error

编辑： Naga Manoj Kumar Lakkoju 2021-4-4

Hello All,

Here is the small function i want to convert to C using Matlab coder.

function []=fun()
x=ones(9,11).*[0:10:100];
var1 = 0;
for t=11:500
  a1=(rand-0.5)*1;
  x(1,t+1)=x(1,t)+a1;
    if x(1,t+1)<(100-var1) || x(1,t+1)>(100+var1)
      x(1,t+1)=x(1,t);
    end
end
end

I am getting size mismatch error: [9,11] ~=[1,11] in Matlab coder.

Things I tried

function []=fun()
    x=bsxfun(@times, ones(9,11),[0:10:100]);      % Changed this line
    var1 = 0;
    for t=11:500
      a1=(rand-0.5)*1;
      x(1,t+1)=x(1,t)+a1;                                          % error in this line 
        if x(1,t+1)<(100-var1) || x(1,t+1)>(100+var1)
          x(1,t+1)=x(1,t);
        end
         if sum(x(:,t+1))/9<100-5
            x(:,t+1)=x(:,t+1)+5;
        end
    end
end

Error : Index exceeds array dimensions. Index value 12 exceeds valid range [1-11] of array x.

function []=fun()
    x=bsxfun(@times, ones(9,11),[0:10:100]);      
    x=repmat(x,[1,1290])                                % Changed this line
    var1 = 0;
    for t=11:1290
      a1=(rand-0.5)*1;
      x(1,t+1)=x(1,t)+a1;                                          
        if x(1,t+1)<(100-var1) || x(1,t+1)>(100+var1)
          x(1,t+1)=x(1,t);
        end
         if sum(x(:,t+1))/9<100-5                           % error in this line 
            x(:,t+1)=x(:,t+1)+5;
        end
    end
end

Error: Sizes mismatch: [1290][9] ~= [14179][9]. in coder and also it is not correct because in my main file dimension of x and other variable is not matching. So I think it is better not to use repmat.

Please give your suggestions. I will try to apply in my code.

Thank You

Manoj

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Naga Manoj Kumar Lakkoju 2021-4-3

在 MATLAB Online 中打开

Here is my code. I haven't used coder till now, So randomly changing stuff based on my errors.

Pleas guide me what should I need to refer, or could you please explain me how should i overcome this index exeeds array dimensions. I know when matlab throws index exeeds array dimensions, I don't know about Matlab coder.

It would be great if you guys helps me with this.

function P_profile=randpower(dt,var1,var3)
p=[[3,179917]               %var1 = var3 = 0
[10,183125]
[6,196000]
[21,196000]
[43,114933]
[969,92483]
[113,92483]
[43,59158]
[21,158547]
[6,158547]
[10,183125]
[3,158547]];
tmax=sum(p(:,1))+41;
coder.varsize('x');         % Since size of x is varying in for loop, so i should tell coder that it is variable size
x=ones(9,11).*[0:10:100];   % getting error in this line: [9x11]~=[1x11]
for t=11:tmax
  a1=(rand-0.5)*1;
  a9=(rand-0.5)*1.25;
  a2=(rand-0.5)*1.5;
  a8=(rand-0.5)*1.75;
  a3=(rand-0.5)*2.0;
  a7=(rand-0.5)*2.25;
  a4=(rand-0.5)*2.5;
  a6=(rand-0.5)*2.75;
  a5=(rand-0.5)*3;
  x(1,t+1)=x(1,t)+a1;
    if x(1,t+1)<(100-var1) || x(1,t+1)>(100+var1)       % loop 1: x(1,11)+a1 value is is writing to x(1,12) So coder gives error "Index exceeds array dimensions. Index value 12 exceeds valid range [1-11] of array x".
      x(1,t+1)=x(1,t);                                  % In matlab it works fine, but coder throws error. 
    end                                                
  x(2,t+1)=x(2,t)+a2;
    if x(2,t+1)<(100-var1) || x(2,t+1)>(100+var1)
      x(2,t+1)=x(2,t);
    end
  x(3,t+1)=x(3,t)+a3;
    if x(3,t+1)<(100-var1) || x(3,t+1)>(100+var1)
      x(3,t+1)=x(3,t);
    end
  x(4,t+1)=x(4,t)+a4;
    if x(4,t+1)<(100-var1) || x(4,t+1)>(100+var1)
      x(4,t+1)=x(4,t);
    end
  x(5,t+1)=x(5,t)+a5;
    if x(5,t+1)<(100-var1) || x(5,t+1)>(100+var1)
      x(5,t+1)=x(5,t);
    end
  x(6,t+1)=x(6,t)+a6;
    if x(6,t+1)<(100-var1) || x(6,t+1)>(100+var1)
      x(6,t+1)=x(6,t);
    end
  x(7,t+1)=x(7,t)+a7;
    if x(7,t+1)<(100-var1) || x(7,t+1)>(100+var1)
      x(7,t+1)=x(7,t);
    end
  x(8,t+1)=x(8,t)+a8;
    if x(8,t+1)<(100-var1) || x(8,t+1)>(100+var1)
      x(8,t+1)=x(8,t);
    end
  x(9,t+1)=x(9,t)+a9;
    if x(9,t+1)<(100-var1) || x(9,t+1)>(100+var1)
      x(9,t+1)=x(9,t);
    end
  if sum(x(:,t+1))/9<100-5
    x(:,t+1)=x(:,t+1)+5;
  end
  if sum(x(:,t+1))/9>100+5
    x(:,t+1)=x(:,t+1)-5;
  end
  temp=x(:,t+1);
  temp(temp<(100-var1))=(100-var1);
  temp(temp>(100+var1))=(100+var1);
  x(:,t+1)=temp;
end
x=x';
P_1s=[];%zeros(3,9);
% P_1s=zeros(0,9);
for i=1:size(p,1)
    P_1s=[P_1s;ones(p(i,1),9)*p(i,2)];
end
P_1s=[ones(12,9)*p(1,2)/9;(P_1s+var3/100*P_1s.*randn(size(P_1s))/2)/9;zeros(30,9)].*x/100;
P_profile=[interp1([0:1:size(P_1s,1)-1],P_1s,[0:dt:size(P_1s,1)-1])];

Thank You.

Happy Sunday

Naga Manoj Kumar Lakkoju 2021-4-4

编辑：Naga Manoj Kumar Lakkoju 2021-4-4

在 MATLAB Online 中打开

Hi dpb,

I have to convert .m file to c/cpp and run generated c/cpp code in visual studio, then compare both results.

When I am converting .m file I am getting size miss match error with this line

x=ones(9,11).*[0:10:100];

Error :

I replaced x = ones(9,11).*[0:10:100]; with x=bsxfun(@times, ones(9,11),[0:10:100]);. even though both are same.

Now In for loop: Even Though I declared x as variable size Why coder is throwing error?

x(1,t+1)=x(1,t)+a1;
    if x(1,t+1)<(100-var1) || x(1,t+1)>(100+var1)       
      x(1,t+1)=x(1,t);                                
    end

Error:

Let say loop 1,

x(1,12)= x(1,11)+a1 In matlab this assignment works fine, but when converting it is throwing error " Index exceeds array dimensions. Index value 12 exceeds valid range [1-11] of array x" As I declared x as variable size coder should assign x(1,11)+a1 value to x(1,12) but it is not doing, instead throwing error. Why?

My question is

1) is declaring x as variable size is correct step or not? if yes then what should be the work around for "index exceeds array dimensions error"

Hope you understand my question.

Thank you,

Naga Manoj Kumar Lakkoju 2021-4-4

编辑：Naga Manoj Kumar Lakkoju 2021-4-4

在 MATLAB Online 中打开

Yeah, Got it. Thank for the questions . Here is updated code.

coder.varsize('x');
x=zeros(9,1300);
x=bsxfun(@times,ones(9,11),[0:10:100]);
x=[x, zeros(9,1279)];

% Not related to previous code.

I have one more doubt

Let say, I have a structure, and When I try to generate code in Matlabcoder it is showing error

If i apply same questions here, a is executed 10 times which means it will have 10 instances. So do I need to pre allocate all the 10 fields? If that is the case then it would be messy if we have more filelds or max loop is so high. there must some way to do this