pseudo code for all n values

Question

0 个投票

n=input('n= ');
A=ones(n);
A(2:n,2)=0;
A(2,2:n)=0;
A(4:n,4)=0;
A(4,4:n)=0;
A(6:n,6)=0;
A(6,6:n)=0

I wrote that code for n=7 but I want this to be true for every n value, how can i convert the code?

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Answer 1

Walter Roberson 2021-4-4

1 个投票

n=input('n= ');
A=ones(n);
A(2:n,2)=0;
A(2,2:n)=0;
A(4:n,4)=0;
A(4,4:n)=0;
A(n-1:n,n-1)=0;
A(n-1,n-1:n)=0;

Possibly 4 is ceil(n/2) but if so you need to decide what you want to do if n is even.

Elif Kalender 2021-4-4

Thank you so much.I will look at it with that perspective.

Answer 2

the cyclist 2021-4-4

1 个投票

Assuming that what you wanted was alternating pattern of 1's and 0's, regardless of how large n is, then this should do what you want:

n=input('n= ');
A=ones(n);
for ii = 2:2:n
    A(ii:n,ii)=0;
    A(ii,ii:n)=0;
end

Elif Kalender 2021-4-4

It really works very well!Thank you so much!