How can I convert x, y, and z which are functions of theta to theta function of x, y, and z?

4 次查看（过去 30 天）
Hwajin Choi
Hwajin Choi 2021-4-6
评论： Hwajin Choi 2021-4-6
Hello,
I have three equations,
eqn1 = 2*L*(y+a)*cos(theta1) + 2*z*L*sin(theta1) + x^2 + y^2 + z^2 + a^2 + L^2 + 2*y*a - l^2 == 0
eqn2 = -L*(sqrt(3)*(x+b)+y+c)*cos(theta2) + 2*z*L*sin(theta2) + x^2 + y^2 + z^2 + b^2 + c^2 + L^2 + 2*x*b + 2*y*c - l^2 == 0
eqn3 = L*(sqrt(3)*(x-b)-y-c)*cos(theta3) + 2*z*L*sin(theta3) + x^2 + y^2 + z^2 + b^2 + c^2 + L^2 - 2*x*b + 2*y*c - l^2 == 0
Every value except theta1,theta2, and theta3 are given.
I want to make the three equations as theta functions having x, y, and z variables.
Like a form of theta1 = .... , theta2 = ....., and theta3 = ....
Please let me know what command I can use to make the conversion.

请先登录，再回答此问题。

采纳的回答

DGM
DGM 2021-4-6
编辑：DGM 2021-4-6
Something like this
syms theta1 theta2 theta3 x y z L l c b a
eqn1 = 2*L*(y+a)*cos(theta1) + 2*z*L*sin(theta1) + x^2 + y^2 + z^2 + a^2 + L^2 + 2*y*a - l^2 == 0
eqn2 = -L*(sqrt(3)*(x+b)+y+c)*cos(theta2) + 2*z*L*sin(theta2) + x^2 + y^2 + z^2 + b^2 + c^2 + L^2 + 2*x*b + 2*y*c - l^2 == 0
eqn3 = L*(sqrt(3)*(x-b)-y-c)*cos(theta3) + 2*z*L*sin(theta3) + x^2 + y^2 + z^2 + b^2 + c^2 + L^2 - 2*x*b + 2*y*c - l^2 == 0
e1 = theta1==solve(eqn1,theta1)
e2 = theta2==solve(eqn2,theta2)
e3 = theta3==solve(eqn3,theta3)
  3 个评论
显示 1更早的评论

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Mathematics 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by