清空筛选条件
清空筛选条件

How can I make a sentence in Alphabetical order

5 次查看（过去 30 天）
Yifei Qiu
Yifei Qiu 2021-4-7
评论： Yifei Qiu 2021-4-7
How can I make the sentence 'the quick brown fox' in alphabetical order
Here is my code, but there are some problem with it. It does not give the answer as I expected.
function[output] = sentenceSort(x)
%%%The input x is a string array which is not in alphabetically
%%%order
%%%The output is the a string array which is in alphabetically order
ind=find(x==' ');%find the position of the space
num=size(ind,2)+1; %determine the number of words in a sentence
count = 1; %set up a variable
words = strings(); %set up an empty string array
for i = 1:num
if i ~= num
words(i)= x(count:ind(i)-1); %fill out each word to corresponding position
count = ind(i)+1;
elseif i== num
words(num) = x(count:length(x));
end
end
for i = 1:num-1
for j = 1:num-1
curr = words(i);
next = words(j+1);
if words(i)<words(j)
output = words
elseif curr > next
words(j) = next;
words(j+1) = curr;
output = words
end
end
end
  2 个评论
Stephen23
Stephen23 2021-4-7
编辑：Stephen23 2021-4-7
Is the goal of this homework to implement a sorting algorithm?
Yifei Qiu
Yifei Qiu 2021-4-7
Yes, and it is not allowed to use the built-in function like "strrep","replaceBetween","regexprep", "return" or other similar functions.

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

Johannes Hougaard
I think a minor modification of your function like this
function[output] = sentenceSort(x)
%%%The input x is a string array or a character array which is not in alphabetically
%%%order
%%%The output is the a string array which is in alphabetically order
if isstring(x) % convert a string to a character array for the find spaces to work
x = char(x);
end
ind=find(x==' ');%find the position of the space
num=size(ind,2)+1; %determine the number of words in a sentence
count = 1; %set up a variable
words = strings(); %set up an empty string array
for i = 1:num
if i ~= num
words(i)= x(count:ind(i)-1); %fill out each word to corresponding position
count = ind(i)+1;
elseif i== num
words(num) = x(count:length(x));
end
end
output = strings(size(words));
for ii = 1:num
wordpos = sum(words < words(ii))+1;
if output(wordpos) == ""
output(wordpos) = words(ii);
else % If two words are identical find the position for the latter
wordpos = find(output == words(ii),1,'last') + 1;
output(wordpos) = words(ii);
end
end
would do the trick without using internal string functions.
If the use of 'sort' is allowed it could simply be sorted by
function[output] = sentenceSort(x)
%%%The input x is a string array or a character array which is not in alphabetically
%%%order
%%%The output is the a string array which is in alphabetically order
if isstring(x) % convert a string to a character array for the find spaces to work
x = char(x);
end
ind=find(x==' ');%find the position of the space
num=size(ind,2)+1; %determine the number of words in a sentence
count = 1; %set up a variable
words = strings(); %set up an empty string array
for i = 1:num
if i ~= num
words(i)= x(count:ind(i)-1); %fill out each word to corresponding position
count = ind(i)+1;
elseif i== num
words(num) = x(count:length(x));
end
end
output = sort(words);

更多回答（1 个）

Sulaymon Eshkabilov
Hi,
Here is an easy solution to your exercise:
CC='the quick brown fox';
ANS =sort(strsplit(strtrim(CC)))
Good luck.

类别

在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by