3D surface plot of integrated function

2 次查看（过去 30 天）
Alyssa Pope
Alyssa Pope 2021-4-7
评论： Alyssa Pope 2021-4-8
I'm trying to make a 3D plot to visually represent a plot I made in 2D. I've tried using cylinder, but it creates the solid in the wrong direction, over the x or z axis instead of the y-axis. Below is my code that creates the 2D plot. Is there a way to basically create a shell around the y-axis and represent it in 3D? I've tried using mesh but I can't seem to get things set up properly. Any help would be greatly appreciated!
function value = Function
r = [1:1:350];
S = 0.001;
T = 2400;
t = 1;
u = ((r.^2)*S)./(4*T.*t);
syms y
Wu = zeros(size(u));
for i = 1:length(u)
Wu(i) = integral(@(y)exp(-y)./(y),u(i),inf);
end
Q = 2400;
value = Q/(4*pi*T)*Wu;
%Plot
f1 = figure('Color', [1 1 1]);
ax1 = axes('FontSize', 18, 'FontWeight', 'bold');
plot(ax1, r, value);
title('Value v Distance');
xlabel('Distance (m)');
ylabel('Value');
set(gca,'Ydir','reverse');
ax = gca;
ax.FontSize = 13;
grid on;
end

请先登录，再回答此问题。

采纳的回答

DGM
DGM 2021-4-7
编辑：DGM 2021-4-7
You can use cylinder. You just need to orient it as needed. For orthogonal rotations, that's easy enough.
r = [1:1:350];
S = 0.001;
T = 2400;
t = 1;
u = ((r.^2)*S)./(4*T.*t);
syms y
Wu = zeros(size(u));
for i = 1:length(u)
Wu(i) = integral(@(y)exp(-y)./(y),u(i),inf);
end
Q = 2400;
value = Q/(4*pi*T)*Wu;
clf
if true % <<-- this is just for sake of testing
[X,Y,Z] = cylinder(value);
h=surf(Y,Z,X)
% make it fancy
shading flat
lightangle(-90,30)
h.FaceLighting = 'gouraud';
h.SpecularStrength = 0.5;
h.AmbientStrength = 0.3;
h.DiffuseStrength = 0.9;
else
ax1 = axes('FontSize', 18, 'FontWeight', 'bold');
plot(ax1, r, value);
title('Value v Distance');
xlabel('Distance (m)');
ylabel('Value');
set(gca,'Ydir','reverse');
ax = gca;
ax.FontSize = 13;
grid on;
end

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Line Plots 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by