Simple arithmetic calculation question

JP
2013 6 20
1 个回答
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0 个投票

Hey just had an easy question that I cant seem to solve. Basically this is what I want to do, but it isnt working... (I think you get the gist of what Im trying to do by looking at the incorrect code)
datastr='0201+03158+04424-06291+05555-004556+003275-090965+014850000003100011F39 02+00364+01836-02658+09456+020408+000839-093108+019160000003100011F39 00004CE4'
data.Q0=str2double(datastr(5:10))/10000;
data.Qx=str2double(datastr(11:16))/10000;
data.Qy=str2double(datastr(17:22))/10000;
data.Qz=str2double(datastr(23:28))/10000;
data.Tx=str2double(datastr(29:35))/100;
data.Ty=str2double(datastr(36:42))/100;
data.Tz=str2double(datastr(43:49))/100;
data.Q02=str2double(((datastr(75:80))/10000)) - data.Q0;
data.Qx2=str2double(((datastr(81:86))/10000)) - data.Qx;
data.Qy2=str2double(((datastr(87:92))/10000)) - data.Qy;
data.Qz2=str2double(((datastr(93:98))/10000)) - data.Qz;
data.Tx2=str2double(((datastr(99:105))/100)) - data.Tx;
data.Ty2=str2double(((datastr(106:112))/100)) - data.Ty;
data.Tz2=str2double(((datastr(113:119))/100)) - data.Ty;

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Iain
Iain 2013-6-20
I can't see your error.
Jan
Jan 2013-6-20
Looking on incorrect code cannot reveal the intention of the code. Please explain "it isn't working" with any details.
Jan
Jan 2013-7-3
Please answer the question for clarification, delete the question, or post the solution. Thanks.

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 采纳的回答

Guru
Guru 2013-7-3

0 个投票

Well the error is pretty obvious. The following lines is using parenthesis incorrectly:
data.Q02=str2double(((datastr(75:80))/10000)) - data.Q0;
data.Qx2=str2double(((datastr(81:86))/10000)) - data.Qx;
data.Qy2=str2double(((datastr(87:92))/10000)) - data.Qy;
data.Qz2=str2double(((datastr(93:98))/10000)) - data.Qz;
data.Tx2=str2double(((datastr(99:105))/100)) - data.Tx;
data.Ty2=str2double(((datastr(106:112))/100)) - data.Ty;
data.Tz2=str2double(((datastr(113:119))/100)) - data.Ty;
You want to place your parenthesis so str2double operates only on the datastr() and not the divide by.
data.Q02=str2double(datastr(75:80))/10000 - data.Q0;
data.Qx2=str2double(datastr(81:86))/10000 - data.Qx;
data.Qy2=str2double(datastr(87:92))/10000 - data.Qy;
data.Qz2=str2double(datastr(93:98))/10000 - data.Qz;
data.Tx2=str2double(datastr(99:105))/100 - data.Tx;
data.Ty2=str2double(datastr(106:112))/100 - data.Ty;
data.Tz2=str2double(datastr(113:119))/100 - data.Ty;
HTH

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