How to define nested function?

23 次查看（过去 30 天）
Aarthika Balakumar
Aarthika Balakumar 2021-4-11
编辑： Cris LaPierre 2021-4-12
I want to define this f fucntion
f = @(x,y)((2.*x+y).*(x<d & y<d)+ (3.*x.*y-1).*(x>d & y<d)+...
(1+x+y).*(x<d & y>d)+ (3.*x+2.*y).*(x>d & y>d)+ ((2.*x(N/2)+y)+...
(3.*x(N/2+2).*y-1)/2).*(x==d & y<d) + (((2.*x+y(N/2))+...
(1+x+y(N/2+2)))/2).*(y==d & x<d)+(((1+x(N/2)+y)+...
(3.*x(N/2+2)+2.*y))/2).*(x==d & y>d)+(((3.*x.*y(N/2)-1)+...
(3.*x+2.*y(N/2+2)))/2).*(y==d & x>d)+(((2.*x(N/2)+y(N/2))+...
(3.*x(N/2+2).*y(N/2)-1)+(1+x(N/2)+y(N/2+2))+(3.*x(N/2+2)+...
2.*y(N/2+2)))/4).*(x==d &y==d));
If i define like this, I am getting error which is mentioned below
Error using
trying1>@(x,y)((2.*x+y).*(x<d&y<d)+(3.*x.*y-1).*(x>d&y<d)+(1+x+y).*(x<d&y>d)+(3.*x+2.*y).*(x>d&y>d)+((2.*x(N/2)+y)+(3.*x(N/2+2).*y-1)/2).*(x==d&y<d)+(((2.*x+y(N/2))+(1+x+y(N/2+2)))/2).*(y==d&x<d)+(((1+x(N/2)+y)+(3.*x(N/2+2)+2.*y))/2).*(x==d&y>d)+(((3.*x.*y(N/2)-1)+(3.*x+2.*y(N/2+2)))/2).*(y==d&x>d)+(((2.*x(N/2)+y(N/2))+(3.*x(N/2+2).*y(N/2)-1)+(1+x(N/2)+y(N/2+2))+(3.*x(N/2+2)+2.*y(N/2+2)))/4).*(x==d&y==d))
Too many input arguments.
Please help me to correct it. Thanks in advance.

请先登录，再回答此问题。

回答（1 个）

Cris LaPierre
Cris LaPierre 2021-4-11
编辑：Cris LaPierre 2021-4-12
Ran in:
I get other errors when I try to implement your function. Perhaps you could share the code you ran that created this error?
The error message suggests you tried calling your function with more than 2 inputs.
To replicate your error, I'll define an anonymous function that has one input, but call it with 3.
a = @(x) (x-5).^2;
% correct - one input, a vector
a([3,5,7])
ans = 1×3
4 0 4
% incorrect - 3 inputs, scalars
a(3,5,7)
Error using solution
Too many input arguments.

类别

在 Help Center 和 File Exchange 中查找有关 MATLAB 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by