I have made several matrics where I tried to read a txt file. I want to perform the below problem I have mentioned. Help is required.

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Mouli Sarkar
Mouli Sarkar 2021-4-13
回答： Shadaab Siddiqie 2021-4-16
Suppose I have a circuit like this below image
here A is activating B and B is activating C.
For this circuit Matrix be like
source node
A B C
-------------------------------------------
A | 0 0 0
Target B | 1 0 0
node C | 0 1 0
That means j th elements are controling i th elements. If A is activating B then there is 1. If A was inhibiting B there will be -1 in the matrix. And the type of the link for inhibition would be like this ---| .
In the above code upto this matrix formation is done.
I want to creat separate .topo file for seperate matrics should be store in separate folder according to there number. And the text file should be in this format I am mentioning below.
Source Target Type
A B 1
B C 1
1 signifies activation
2 signifies inactivation
how can do this part of coding?
Attemped code:
----------------------------
A=readtable('topo.txt')
for iter=1:size(A,1)
vec(:,:,iter)=[A{iter,2:4};A{iter,5:7};A{iter,8:10}];
end
disp(vec);
Input text file:
1,0,-1,-1,0,0,-1,0,0,0
2,0,-1,-1,0,0,0,0,0,0
3,0,-1,-1,0,0,0,0,1,0
4,0,-1,0,0,0,-1,-1,0,0
5,0,-1,0,0,0,-1,0,0,0
6,0,-1,0,0,0,-1,1,0,0
7,0,-1,0,0,0,0,-1,1,0
8,0,-1,0,0,0,0,0,-1,0
9,0,-1,0,0,0,0,0,1,0
10,0,-1,0,0,0,0,1,-1,0
11,0,-1,0,0,0,0,1,0,0
12,0,-1,0,0,0,0,1,1,0
13,0,-1,0,0,0,1,0,0,0
14,0,-1,0,0,0,1,1,0,0
15,0,-1,1,0,0,0,0,0,0
16,0,-1,1,0,0,0,0,1,0
17,0,-1,1,0,0,1,0,0,0
18,0,0,0,0,0,0,1,1,0
19,0,0,0,0,0,1,1,0,0
20,0,0,0,1,0,0,1,0,0
21,0,0,0,1,0,0,1,1,0
22,0,0,1,1,0,0,0,1,0
  1 个评论
Walter Roberson
Walter Roberson 2021-4-13
1,0,-1,-1,0,0,-1,0,0,0
2,0,-1,-1,0,0,0,0,0,0
If I understand that correctly, the first line says that line 1, B inhibits A and C inhibits A, B inhibits C; and the second line says Line 2, B inhibits A and C inhibits A.
If I undestand correctly, that should lead to output
Source Target Type
B A 2
C A 2
C B 2
Source Target Type
B A 2
C A 2
Is that correct? Is that all there is to it?

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回答（1 个）

Shadaab Siddiqie
Shadaab Siddiqie 2021-4-16
From my understanding you want to find the index of the matrix with source and target nodes which follows certain condition (for example: there value is 1). Here is an example to show how you can you find() function to get the index of a matrix with certain condition and get the nodes values.
>> M = [0 1 0; 1 0 0; 0 0 1]; % source and target matrix
>> m1 = ["A" "B" "C"]; % maping the names of nodes
>> [row,col] = find(M==1); % get all index with i->j
>> m1(row)
ans =
1×3 string array
"B" "A" "C"
>> m1(col)
ans =
1×3 string array
"A" "B" "C"

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