cfit object doesn't work with 'plot' or 'differentiate'
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Hello,
I stored a cfit obj to hard disc. It looks like:
General model:
ans(xd) = off+amp./(1+exp(-a.*(xd-b)))
Coefficients (with 95% confidence bounds):
off = -4.047 (-4.054, -4.041)
amp = 8.179 (8.169, 8.189)
a = 4.053 (4.034, 4.073)
b = 2.271 (2.27, 2.273)
In the process of creating the obj I was able to plot it and to calculate the derivatives.
Now I want to come back to these data and tried:
>>plot(cfObj)
but receive:
Error using cfit/plot (line 111)
Error evaluating CFIT function:
Error while trying to evaluate CFIT model: obj:
Error while trying to evaluate FITTYPE function obj:
Argument must contain a string or function_handle.
For:
>>differntiate(cfObj, x)
I receive:
Error using cfit/feval (line 31)
Error while trying to evaluate CFIT model: fitobj:
Error while trying to evaluate FITTYPE function obj:
Argument must contain a string or function_handle.
Error in cfit/differentiate (line 33)
f1 = feval(fitobj,x+ms);
Can anyone please help out with that? Sure I can recreate the fit from the coefficients, but I think it is not meant to be like that.
Thanks,
Kai
2 个评论
Onno Broekmans
2013-7-1
Your fit results are definitely not useless. You can use coeffvalues(cfObj) to get the coefficient values from the fit manually, and then plot them using:
fitCoeffs = num2cell(coeffvalues(cfObj));
fitFun = @(off,amp,a,b,xd) off+amp./(1+exp(-a.*(xd-b)));
plot(x, feval(fitFun, fitCoeffs{:}, x, '-r');
(Warning: untested code, so there might be minor syntax errors in there. I'm assuming your x data is in the variable 'x').
Note that this is what plot(cfObj,x) does internally, so the results are exactly the same :)
采纳的回答
Onno Broekmans
2013-7-1
I can confirm this behavior (see code to reproduce at the bottom). Unfortunately, it also affects parallel processing: if you try to perform a large number of fits in parallel, using a 'parfor' loop, the resulting cfit objects are "broken" in the way described by Kai.
Unless I've missed something, I'd consider this a bug. I've filed a Service Request (ID: 1-NE8ATH) with TMW. I'll get back to this thread when I hear back.
As a workaround, you could try manually evaluting the fit's anonymous function, and using the coeffvalues() function to retrieve the coefficients from the cfit object (that does work fine).
- Onno
Code to reproduce the issue:
%%Generate some random data, and plot it
data_x = 1:50;
data_y = (2.* data_x) + randn(size(data_x)) + 5;
figure;
plot(data_x, data_y, '.b');
title('Original data');
%%Fit the data using a simple model
model = @(A, B, x) A.*x + B;
ftype = fittype(model);
fopt = fitoptions(ftype);
fopt.StartPoint = [1 1];
f = fit(data_x(:), data_y(:), ftype, fopt);
%%Plot the fit
figure;
hold on;
plot(data_x, data_y, '.b');
plot(f, '-r');
hold off;
title('Fitted data');
%%Store cfit object on disk, and then retrieve it again
save('fit.mat', 'f');
clear('f');
load('fit.mat');
figure;
hold on;
plot(data_x, data_y, '.b');
plot(f, '-r'); % <-- crash here:
% Error using cfit/plot (line 113)
% Error evaluating CFIT function:
% Error while trying to evaluate CFIT model: obj:
% Error while trying to evaluate FITTYPE function obj:
% Argument must contain a string or function_handle.
hold off;
title('Fitted data (fit loaded from disk)');
3 个评论
Onno Broekmans
2013-8-1
I forgot to post back, but TMW confirmed the issue (early July), and said they had their developers working on it.
Jon Cherrie
2013-8-21
更多回答(1 个)
Andrei Bobrov
2013-6-26
编辑:Andrei Bobrov
2013-6-26
x = (0:.01:4)'; %
y = -4 + 8./(1+exp(4.*(x - 2))) + .5*randn(numel(x),1); % your data
ftfun = fit(x,y,fittype(@(a,b,c,d,x)a + b./(1+exp(c.*(x - d)))),...
'Startpoint',[1 1 1 1])
dft = differentiate(ftfun,x);
plot(x,[y,ftfun(x),dft])
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