why I can't use "linalg::substitute" in R2013a?

if true
>>aaas=zeros(20,2);
>>aaaf=rand(10,2);
>> linalg::substitute(aaas,aaaf,1,1)
end
It tells me "Error: Unexpected MATLAB operator."

回答(1 个)

linalg::substitute(aaas,aaaf,1,1)
Is a MuPAD command. You'll have to run it from within MuPAD. To Open MuPAD, either run the App from the Apps tab or run:
>>mupad
for more information on it:
doc mupad

1 个评论

Thanks for fast response. Is there a regular command with the same function?

此问题已关闭。

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提问:

2013-6-26

关闭:

2021-8-20

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