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why I can't use "linalg::substitute" in R2013a?
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if true
>>aaas=zeros(20,2);
>>aaaf=rand(10,2);
>> linalg::substitute(aaas,aaaf,1,1)
end
It tells me "Error: Unexpected MATLAB operator."
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回答(1 个)
Sean de Wolski
2013-6-26
linalg::substitute(aaas,aaaf,1,1)
Is a MuPAD command. You'll have to run it from within MuPAD. To Open MuPAD, either run the App from the Apps tab or run:
>>mupad
for more information on it:
doc mupad
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