How to set timeout to a function

Question

Javier Checa 2021-4-16

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/803971-how-to-set-timeout-to-a-function

回答： Giovanni Soleti 2024-9-11，11:02

Hi everyone, I need to stop the execution of a function if finish a specific time. Specifically the part of the program where i need to implement it is when i call a function to create a regressor:

[trainedModel, validationRMSE] = trainRegressionModelLinear(T, KFolds);

I have left the program running and it never finish the function so i wanted to exit the function and continue the rest of the program. The function works because i change the data "T" that i insert in the function and i get a trainedModel with its value but with long data T i think no works.

There is a example that i need to do but with try- catch doesnt work:

try 
[trainedModel, validationRMSE] = trainRegressionModelLinear(T, KFolds);
catch (*time out finish*)
    validationRMSE = "Error";
    trainedModel = [];
end

I find some information how said that i need to use parallel pool, batch(), parfeval() or a timer but i dont understand what function is useful for my situation. I already use parallel pool with 4 workers because is better to train regressor but to apply the time out no idea.

Thanks so much for the help and sorry if I have explained badly because the english is not my native language.

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Answer 1

Edric Ellis 2021-4-19

2
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https://ww2.mathworks.cn/matlabcentral/answers/803971-how-to-set-timeout-to-a-function#answer_678787

在 MATLAB Online 中打开

You could use parfeval to do this, but I'm not sure how you might fit that in with the rest of your parpool usage. Here's the simplest case where you use wait with a single future:

fut = parfeval(@pause, 0, 20); % Dummy function - you'd use your training function here
ok = wait(fut, 'finished', 4); % Wait for up to 4 seconds for 'fut' to finish
if ~ok
    disp('Did not finish in time.')
else
    disp('Did finish in time.')
end