rows extraction in matrix depending on a column value

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I have a 50x50 matrix and n that the last row has 0,1,2 at different locations ie., 0 n 10 rows,1 n 20 rows ad 2 in 20 rows, so depending on the column value how can i extract all rows containing 0 at 50th column and save them in to a single variable
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Sean de Wolski
Sean de Wolski 2013-6-28
A small example of your matrix and expected results would make this much easier to grasp.
PK
PK 2013-6-28
编辑:PK 2013-6-28
@Sean de Wolski A=[1 2 3 0; 1 2 5 0;5 8 6 1;6 8 7 0;5 4 7 2;6 5 8 0] so in this there are 6 rows and depending on fourth element of the row all the rows containing same number are to be pinned up to a single variable ie.,rows 1,2,4,6 are to be stored to a single variable and row 3 to another and row 5 to another.

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采纳的回答

Image Analyst
Image Analyst 2013-6-28
Try this:
% Generate sample data
A=[...
1 2 3 0;
1 2 5 0;
5 8 6 1;
6 8 7 0;
5 4 7 2;
6 5 8 0]
% Get last column
lastColumn = A(:, end);
% Get zeros
A0 = A(lastColumn == 0, :)
% Get zeros
A1 = A(lastColumn == 1, :)
% Get zeros
A2 = A(lastColumn == 2, :)
In the command window:
A =
1 2 3 0
1 2 5 0
5 8 6 1
6 8 7 0
5 4 7 2
6 5 8 0
A0 =
1 2 3 0
1 2 5 0
6 8 7 0
6 5 8 0
A1 =
5 8 6 1
A2 =
5 4 7 2

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