defining the mean of a values inside a matrix

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Greetings,
I was trying to find a way to find the mean of the values inside the matrix. For example, [1,2,3,4,5,6] I want to find the average between 1 & 2/ 2&3/3&4/4&5 and so on
I tried to do a for-loop but It doesnt seemt to work when I compare the values to hand calculations
z18=(-length(theta)/2+(0:length(theta)))'*h; % Travel of total 18 layers %%%% 19 values due to neutral axis
z18t=((-length(theta)/2+(0:length(theta)))'*h)/2; %% I took this approach as well but it does not work
for t=1:length(z18)
tt=max(1,(t-1));
ttt=min(length(z18), t+1);
tttt(t)=mean(z18(tt:ttt));
end

采纳的回答

Walter Roberson
Walter Roberson 2021-4-18
A = randi(9, [1 6])
A = 1×6
8 2 2 3 6 3
[A(1), A(1:end-1) + diff(A)/2, A(end)]
ans = 1×7
8.0000 5.0000 2.0000 2.5000 4.5000 4.5000 3.0000

更多回答(1 个)

Khalid Mahmood
Khalid Mahmood 2021-4-18
编辑:Khalid Mahmood 2021-4-18
Further methods
1: movmean(matrix,windowsize) it calculates running mean but considers only windowsize elements
examples:
mm2=movmean(z18,2)
mm3=movmean(z18,3)
Using for loop to calculate running mean as [z18(1), (z18(1)+z18(2)/2, ( (z18(1)+z18(2) )/2+ z18(3) )/3,...]
mm=z18(1);
for p=2:length(z18)
mm(p)=(mm(p-1)+z18(p))/p;
end
  8 个评论
Sufia Tanveer
Sufia Tanveer 2021-4-18
I learnt more from comments than actual question!
Khalid Mahmood
Khalid Mahmood 2021-4-19
And remember, In moving mean, last value of source vector is not copied in result. It is actually calculated. So moving mean methods, movmean, mm code (to rduce in a mean way), and vectorised cumsum./[1:src] methods are actual moving mean methods. Those are just different types of moving means

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