finding the corresponding value in a for loop
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Hi,
I have created a for loop which loops through a number of columns on the image and finds the number of times that 0 (black colour) occurs in that column
for b=1:50
[c]=numel(find(img597(:,b,1)==0))
end
How do I find the corresponding value ( the column) where the maximum number of 0s has occured. The answer has to be 50
3 个评论
Jonas
2021-4-19
the easiest way is to use
nrOfZeros=sum(img597(:,:,1)==0);
which gives you a row vector containing the number of zeros per column
colNrs=find(nrOfZeros==max(nrOfZeros),sum(nrOfZeros==max(nrOfZeros)))
colNrs then contains the numbers of columns with the maximum number of 0
Atheeb Amjard
2021-4-19
Jonas
2021-4-20
it's the same procedure but with the first snippet being
nrOfZeros=sum(img597(:,:,1)==0,2);
which gives you a column vector with the number of 0 per row
采纳的回答
David Hill
2021-4-19
[~,idx]=max(sum(img597==0));
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