Computing an integral inside a function

Hi guys!
I need to compute an integral inside a function. To compute an integral I use int function, first argument of which is the function to be integrated. I specify this function inside my big function
function [Put]=Putprice(S,K,r,q,T,a1,a2,b1,b2,c,beta)
function y=b(s)
y=b1*s+b2;
end
alpha=r-q+b;
f=a^2*exp(-2*abs(beta)*int(alpha,s,0,u));
tau=int(f,u,0,T);
all the other parameters are specified. What's wrong?
Daniel.

回答(2 个)

It really helps when you show what error you are getting and how you are calling the function at the command line. Give people a simple example so that they can reproduce your error.
int() expects symbolic variables, are you using symbolic variables here?
If not, look at the help for integral()
value = integral(@(x) 1/sqrt(2*pi)*exp(-x.^2./2),0,3)

2 个评论

Yes, you are right. I want to compute a definite integral, so the function integral() suits here best.
The problem is that when I define a function for this integral(), it contains another integral, which is symbolic...
b = @(s) r-q+b1*s+b2;
a = @(u) (a1*u+a2)^2;
tau=integral(a*exp(-2*abs(beta)*int(b,s,0,u)),0,T);
syms s;
b = r-q+b1*s+b2;
a = @(u) (a1*u+a2)^2*exp(-2*abs(beta)*int(b,s,0,u));
tau=integral(a,0,T);
Still cannot compute tau :(

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Integral is for numerical integration. What are you expecting the result in?
Once you compute the symbolic integral use subs to evaluate the result:
Or use matlabFunction to convert the integrated function into a matlab function handle:
Ofcourse I am assuming that you know what the other parameters are.

1 个评论

I expect a number at the end. T=1 and I want to calculate tau. should I use smth like this?
a = @(u) (a1*u+a2)^2*exp(-2*abs(beta)*matlabFunction(int(b,s,0,u)));
I'm really stuck at this step

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提问:

2013-6-30

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