Matrix line by line
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how can i go through a matrix line by line?
I have this matrix and would like to have the value of a spinner depending on the value.
x = [1:1:5; 6:1:10]
采纳的回答
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nrow = size(x,1);
for K = 1 : 5
spin = randi(nrow);
randrow = x(spin,:)
end
3 个评论
TheDice
2021-4-20
It sounds like you want linear indexing, but row by row
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nent = numel(x);
xt = x.';
for K = 1 : 5
spin = randi(nent);
randval = xt(spin);
[spin, randval]
end
The entries in the array happen to all be equal to their index when operating with that scheme, except for the last few, and you can see in my example that indeed it happened to pull out the stored value (0) at index 37
TheDice
2021-4-20
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