Matrix line by line

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TheDice
TheDice 2021-4-20
评论： TheDice 2021-4-20
how can i go through a matrix line by line?
I have this matrix and would like to have the value of a spinner depending on the value.
x = [1:1:5; 6:1:10]

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Walter Roberson
Walter Roberson 2021-4-20
Ran in:
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nrow = size(x,1);
for K = 1 : 5
spin = randi(nrow);
randrow = x(spin,:)
end
randrow = 1×5
11 12 13 14 15
randrow = 1×5
26 27 28 29 30
randrow = 1×5
26 27 28 29 30
randrow = 1×5
11 12 13 14 15
randrow = 1×5
31 32 33 34 35
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Walter Roberson
Walter Roberson 2021-4-20
Ran in:
It sounds like you want linear indexing, but row by row
x = [1:1:5; 6:1:10; 11:15; 16:20; 21:25; 26:30; 31:35; [36, 0, -1, nan, nan]];
nent = numel(x);
xt = x.';
for K = 1 : 5
spin = randi(nent);
randval = xt(spin);
[spin, randval]
end
ans = 1×2
1 1
ans = 1×2
37 0
ans = 1×2
19 19
ans = 1×2
35 35
ans = 1×2
30 30
The entries in the array happen to all be equal to their index when operating with that scheme, except for the last few, and you can see in my example that indeed it happened to pull out the stored value (0) at index 37
TheDice
TheDice 2021-4-20
Thank you. Is it possible to fill the matrix from top to bottom not from left to right?

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