How can I find X smallest numbers in a Matrix?
3 次查看(过去 30 天)
显示 更早的评论
I have a 480 by 640 matrix, and I would like to find 4 smallest number ( or closest values to zero).
0 个评论
采纳的回答
Matt J
2013-7-2
Xs=sort(X(:));
FourSmallest = Xs(1:4);
7 个评论
Image Analyst
2013-7-2
You may have more than 4 pixels having the 4 smallest values. You can use ind2sub() or find
[rows1, columns1] = find(yourImage == Xs(1));
[rows2, columns2] = find(yourImage == Xs(2));
[rows3, columns3] = find(yourImage == Xs(3));
[rows4, columns4] = find(yourImage == Xs(4));
Matt J
2013-7-2
编辑:Matt J
2013-7-2
in Xind it return the indices as one number
In case it matters, note that the "one number" will work as an index, even when used with the original 480x640 matrix, e.g.,
>> X=reshape((1:20)*10,4,5).'
X =
10 20 30 40
50 60 70 80
90 100 110 120
130 140 150 160
170 180 190 200
>> [Xs, Xind]=sort(X(:));
>> X(Xind(4))
ans =
40
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!