How to draw a rectangle over a patch?

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Nathaniel Levi Blank
编辑： giannit 2021-5-7
Hello, I need to draw a rectangle with curved edges over a background that I created using patch(). For the rectangle I am using the function rectangel() because it has a curvature property. I know that other functions have a property like 'layer' that lets me place things on top of others, but rectangle() doesn't have this property. I am open to alternative methods of creating the rounded rectangle or the background so that I can get the final result.
Thanks in advance!

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Jan
Jan 2021-4-21
编辑：Jan 2021-4-21
Ran in:
You can draw into different AXES objects, while the top one is invisible:
FigH = figure;
Axes1H = axes(FigH, 'XLim', [0, 100], 'YLim', [0, 100]);
Axes2H = axes(FigH, 'XLim', [0, 100], 'YLim', [0, 100], ...
'Visible', 'off'); % On top of Axes1H
patch(Axes1H, [20, 20, 80, 80], [10, 90, 90, 10], [1,0,0])
rectangle(Axes2H, 'Position', [10, 40, 80, 30], 'Curvature', 0.5)
  2 个评论
giannit
giannit 2021-5-7
编辑：giannit 2021-5-7
You can decide who stays at top simply using the Z-axis coordinates of patch.
This will plot the same as Jan
Z = 0*ones(1,4);
patch([20, 20, 80, 80], [10, 90, 90, 10], Z, [1,0,0])
rectangle('Position', [10, 40, 80, 30], 'Curvature', 0.5)
while with Z = 1*ones(1,4) it will plot the patch over the rectangle.

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