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unique function but with repeated groups

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Haneya Qureshi
Haneya Qureshi 2021-4-24
回答： Haneya Qureshi 2021-4-24
I have= [1 1 1 5 5 5 1 1]
I want first indices of each repeat values: [1 4 7]
i.e., the first group of repeated 1's start at index 1, the second group of repeated 5's start at index 4 and the third group of repeated 1s start at index 7
I am trying unique function, but it misses out the last group of 1s.
[~,ic,~]=unique([1 1 1 5 5 5 1 1], 'stable')
gives me [1 4] and not [1 4 7]

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Haneya Qureshi
Haneya Qureshi 2021-4-24
Figured it out!
G= [1 1 1 5 5 5 1 1]
temp = [0, diff(G(:)')==0,0];
index = strfind(temp,[1 0]);

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