solve non-linear optimization problem

how to maximize this nonlinear function z and find the value of x and y,
z= 0.031 {0.009[exp⁡(x-z)-1]+x/1.14}-(-1+√(1+y^4/x))/y
10<=x<=20 and y>=0

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Matt J
Matt J 2021-4-26
With fmincon, if you have Optimization Toolbox.

19 个评论

The main problem of this optimization problem, the objective function z is calculated in terms of the same value of z
You "objective" is really an equality constraint:
After this assumption, the problem contains three decision variables x,y and z?
How fminco function solve this optimization problem
Min -Z
St
Z-....=0
d>=100
d<=300
v>=0
Did you already get it to work on your original problem, and if so how is this new version different?
I want to ask, can this function solve this optimization problem subject to non-linear constraints
Yes, see the nonlcon parameter of fmincon.
I want to ask, can this function solve this optimization problem subject to non-linear constraints
Yes, see this example in the documentation:
Note that you don't really have to ensure that the initial guess satisfy the constraints, as they do in the example, but it can be beneficial to do so.
Can you help me in writing this MATLAB function Min -Z St z= 0.031 {0.009[exp(x-z)-1]+x/1.14}-(-1+√(1+y^4/x))/y 10<=x<=20 and y>0
fmincon thinks you can get an arbitrarily large result if you make y arbitrarily large.
format long g
obj = @(xyz) -xyz(3);
A = []; b = []; Aeq = []; beq = [];
lb = [10, realmin, -inf];
ub = [20 1e9 1e9];
nl = @(x,y,z) 0.031*(0.009*(exp(x-z)-1)+x./1.14)-(-1+sqrt(1+y^4./x))./y - z
nl = function_handle with value:
@(x,y,z)0.031*(0.009*(exp(x-z)-1)+x./1.14)-(-1+sqrt(1+y^4./x))./y-z
nonlcon = @(xyz) deal(nl(xyz(1), xyz(2), xyz(3)), []);
xyz0 = [.1 .2 .3]
xyz0 = 1×3
0.1 0.2 0.3
[best, fval] = fmincon(obj, xyz0, A, b, Aeq, beq, lb, ub, nonlcon)
Local minimum found that satisfies the constraints. Optimization completed because the objective function is non-decreasing in feasible directions, to within the value of the optimality tolerance, and constraints are satisfied to within the value of the constraint tolerance.
best = 1×3
17.9264664551072 190469849.537475 999999999.999999
fval =
-999999999.999999
Please re-check your equations. I suspect that the sqrt() is intended to extend over the /y as well, which is not what you have coded.
Thank you very much for your quick reply,
when i tried this code, gave me error in this line
[best, fval] = fmincon(obj, v0, A, b, Aeq, beq, lb, ub, nonlcon)
What was the error message?
Error using barrier
Nonlinear constraint function is undefined at initial point. Fmincon cannot continue.
Error in fmincon (line 798)
[X,FVAL,EXITFLAG,OUTPUT,LAMBDA,GRAD,HESSIAN] = barrier(funfcn,X,A,B,Aeq,Beq,l,u,confcn,options.HessFcn, ...
Error in nonlinear (line 11)
[best, fval] = fmincon(obj, vdJ0, A, b, Aeq, beq, lb, ub, nonlcon)
please post the complete code you used.
format long g
obj = @(xyz) -xyz(3);
A = []; b = []; Aeq = []; beq = [];
lb = [100, realmin, -inf];
ub = [300 1e9 1e9];
%nl = @(x,y,z) 0.031*(0.009*(exp(x-z)-1)+x./1.14)-(-1+sqrt(1+y^4./x))./y - z
w=10^-15*exp(-2.897*10^22*25^-1);
nl = @(x,y,z) 0.055*(w*(exp(5802*(x-19.5*z))-1)+x./1.14)-(-1+sqrt(1+0.5272*y^4./x^2.))/(2.6328 *10^9*y) - z;
nonlcon = @(xyz) deal(nl(xyz(1), xyz(2), xyz(3)), []);
xyz0 = [.1 .2 .3];
[best, fval] = fmincon(obj, xyz0, A, b, Aeq, beq, lb, ub, nonlcon)
w=10^-15*exp(-2.897*10^22*25^-1);
You badly need to rescale !!
exp(-1158800000000000000000) is about
Effectively your w is 0.
Thank you very much, I will rescale it

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