Randomly splitting of a number in a sum format.

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rohini more 2021-4-27

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https://ww2.mathworks.cn/matlabcentral/answers/814500-randomly-splitting-of-a-number-in-a-sum-format

评论： rohini more 2021-4-27

采纳的回答： Bruno Luong

Suppose n=5

we can split this number like

5=3+2,4+1..... so on.

But I just want to select a only one sum but randomly and I would like to specify by using varible

5=1+3+1

then n_{1}=1, n_{2}=3, n_{3}=1.

How to implement matlab code for any value of n as per above method.

Please help me.

Thanks in advance.

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John D'Errico 2021-4-27

编辑：John D'Errico 2021-4-27

PLEASE STOP ASKING THE SAME QUESTION!

You have asked 6 questions so far on ANSWERS. 5 of them have been essentially duplicates. The rest of them had answers already, but I just closed the latest one, and will now close further duplicate questions by you. You have already gotten multiple answers to your question.

John D'Errico 2021-4-27

编辑：John D'Errico 2021-4-27

No. There have been multiple questions about random partitions of a set. Learn how to find the set of all partitions, then choose one randomly. You cannot create variable names on the fly, and to the extent that you can do so, you SHOULD not. Instead, learn to use vectors.

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采纳的回答

Bruno Luong 2021-4-27

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https://ww2.mathworks.cn/matlabcentral/answers/814500-randomly-splitting-of-a-number-in-a-sum-format#answer_685920

编辑：Bruno Luong 2021-4-27

在 MATLAB Online 中打开

n = 10;
for j=1:10
    r = n;
    i = 1;
    clear s
    while r > 0
        s(i) = ceil(r*rand);
        r = r-s(i);
        i = i+1;
    end
    disp(s)
end
     4     2     4

     8     1     1

     7     3

     4     2     2     1     1

     8     1     1

     7     1     1     1

     7     1     1     1

    10

     8     2

     1     9

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Bruno Luong 2021-4-27

Ops I have a typo in my code, can you try again.

rohini more 2021-4-27

Now its working . Thank you very much.

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Bruno Luong 2021-4-27

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/814500-randomly-splitting-of-a-number-in-a-sum-format#answer_686115

编辑：Bruno Luong 2021-4-27

在 MATLAB Online 中打开

This code will generate "uniform" partition distribution, in the sense that all possible partition has equal probability:

n = 10;
% This part is done once if n is fix
L = 1:n;
p = arrayfun(@(k) nchoosek(n-1,n-k), L);
e = [0, cumsum(p)];
e = e/e(end);
% This part must be repeated when an new random partition is requested
[~,k] = histc(rand,e);
h = diff([0 sort(randperm(n-1,n-k)) n]);
H = mat2cell(L, 1, h)
H = 1×2 cell array
    {[1 2 3 4 5]}    {[6 7 8 9 10]}