clc; clear;
dt = 0.5;
Glucose = zeros(1,361);
Glucose(1,1) = 6000;
Glucose_Released = 110;
Glucose_Used = zeros(1,361);
Usage_Fraction = zeros(1,361);
t = 0:dt:180; % We need to generate a time vector for our plot
for k = 2:length(t)
Glucose_Used(k) = Glucose(k) * Usage_Fraction(k); % Based on Euler?sformula
Glucose(k-1) = Glucose(k) + [Glucose_Released(k) - Glucose_Used(k)]*dt;
end
Please help!!

3 个评论

Question edited to format code.
@Sudhaunsh Deshpande, looks like David hit the nail on the head. Let us know if you have any other questions.
It did kinda work, the values are now zero which means that my guy is dead, but hey atleast the damn thing runs!

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 采纳的回答

You have defined Glucose_Released as a scaler value
Glucose_Released = 110;
You are then trying to index it, which will cause an error
Glucose_Released(k)

6 个评论

The thing is Glucose_Released is the rate of glucose being released.
So the only option is:
Glucose_Released a matrix of (361X1) with the value 110
is that what you mean?
It is your calculation - I am merely pointing out that trying to index a scaler is the cause of your error. If the rate of glucose release is invariant, do you need to index it at all - or does Glucose_Released really represent the amount of glucose released over time? I don't know - as I say I have no idea what you are doing, you asked for the source of the error: I provided it.
Okay that actually makes sense
thank you :)
so how did you modify the script in the end to make it work?
Pardon my text editing:)
for i=1: length (t) Glucose Used(i) = Glucose(i) * Usage_Fraction(i); Glucose(i+1) = Glucose(i) + (G lucose_Released(i) Glucose_Used(i)) *dt; Insulin breakdown(i) = Insulin(i)/k; Insulin(i+1) Insulin(1) [Insulin_Secreted(i) Insulin_breakdown (1)] *dt;
You have
Glucose(i+1) = Glucose(i) + (G lucose_Released(i) Glucose_Used(i)) *dt
We can assume an accidental space,
Glucose(i+1) = Glucose(i) + (Glucose_Released(i) Glucose_Used(i)) *dt
but there needs to be something between Glucose_Released(i) and Glucose_Used(i)

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