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I have a cellArray data. Could you tell me how I can extract the first column of this cellArray data without depending any character and number?

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sermet
sermet 2013-7-10
cellArray =
'A29G0202 465254.432 4066809.025'
'A29G0008 499252.083 4042876.84'
'A29G0014 494404.625 4047958.526'
Name Size Bytes Class Attributes
cellArray 22x1 ... cell
%I want to extract first column of cellArray. (A29G0202, A29G0008, A29G0014)

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采纳的回答

Andrei Bobrov
Andrei Bobrov 2013-7-10
cellArray ={'A29G0202 465254.432 4066809.025';
'A29G0008 499252.083 4042876.84';
'A29G0014 494404.625 4047958.526'};
a = regexp(cellArray,'^([a-zA-Z]*\d*)*','match');
out = cat(1,a{:});

更多回答（2 个）

Jan
Jan 2013-7-10
No, the cell array you show us has one column only, as you can see by the size {22 x 1}. The elements of the cells contain the complete rows as a string and this is obviously a bad idea. So I suggest to improve the method you have used to create this cell array, such that you get something like this directly:
cellArray = { ...
'A29G0202', '465254.432', '4066809.025'; ...
'A29G0008', '499252.083', '4042876.84'; ...
...
}
Then the extraction is trivial:
cellArray(:, 1)
Perhaps something like this helps to create the cell array:
textscan(fid, '%s %s %s');
dpb
dpb 2013-7-10
MATL
>> t=textscan(char(cellArray),'%s %*[^\n]');
>> reshape(char(t{:}),length(cellArray,[])
ans =
A29G0202
A29G0008
A29G0014
>>
Be easier if you would use
'CollectOutput', true
when you read the data to begin with.

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