How to delete multiple elements from array in step by step process and how to store remaining elements in array

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BHUKYA VENKATESH
BHUKYA VENKATESH 2021-5-1
评论： BHUKYA VENKATESH 2021-5-4
I have an array A=[1 0.2 7 0.5 3 8]
I want to delete lowest number from this array
A(A==0.2)=[]
A=[1 7 0.5 3 8]
now again I want to delet lowest number from this
A(A==0.5)=[]
A=[1 7 3 8]
Now, How do I store different lengths array for future reference.
array={[1 0.2 7 0.5 3 8];
[1 7 0.5 3 8];
[1 7 3 8];
[7 3 8];
[7 8];
[8]}
is it possible with while loop ???

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采纳的回答

DGM
DGM 2021-5-2
For storing dissimilar size/type objects, you can use a cell array:
A = [1 0.2 7 0.5 3 8];
B = cell(numel(A),1);
B{1} = A;
for v = 2:numel(A)
thisvec = B{v-1};
[~,idx] = min(thisvec);
thisvec(idx) = [];
B{v} = thisvec;
end
B{:}
gives
ans =
1.0000 0.2000 7.0000 0.5000 3.0000 8.0000
ans =
1.0000 7.0000 0.5000 3.0000 8.0000
ans =
1 7 3 8
ans =
7 3 8
ans =
7 8
ans =
8
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DGM
DGM 2021-5-2
编辑：DGM 2021-5-2
You could use a while loop, but there's no good reason to use a while loop if the number of iterations is known. It's a lot harder to accidentally make a for-loop become infinite.

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更多回答（1 个）

Jan
Jan 2021-5-2
A = [1 0.2 7 0.5 3 8];
nA = numel(A);
array = cell(nA, 1);
for k = 1:nA
array{k} = maxk(A, nA - k + 1);
end

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