Is it possible to generate specific random numbers?
1 次查看(过去 30 天)
显示 更早的评论
The generation of unique random numbers is done simply through randperm.
example
function idx=RandNumberSequence(Key,N)
% using Key as seed to the used random number generator.
Key = max(cumsum(double(Key))) ;
s=rng(Key); % Set the random number generator seed
idx=randperm(N);
end
The question is, given certain N random numbers, is it possible to select the Key that generates these N numbers?
let N=10, let te random numbers be 89, 70, 10, 12, 67, 25, 200, 18, 90, 86
Key=? (to be selected)
0 个评论
采纳的回答
Steven Lord
2021-5-2
Sure.
seedvalue = 0;
expected = [89 70 10 12 67 25 200 18 90 86];
rng(seedvalue, 'twister');
actual = randperm(max(expected), numel(expected));
while ~isequal(actual, expected)
seedvalue = seedvalue + 1;
rng(seedvalue, 'twister');
actual = randperm(max(expected), numel(expected));
end
It may take a while. This assumes you haven't manually created a state vector (which would be an advanced maneuver.)
If you're asking if there's a clever way to directly go from the sequence to the seed value, I'm not aware of any offhand.
If you know you're going to need or want to reproduce a given sequence, record the seed before generating the sequence.
2 个评论
Steven Lord
2021-5-3
Yes, this code could be parallelized through the use of parfor to sweep the seed space. But if speed is of the essence the best solution is to record the seed before you generate the sequence rather than trying to determine the seed after the fact.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Sources 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!