FIR Filter 10th order with a for loop

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Abd Alsalam Al Saell
评论： David Fletcher 2021-5-3
i'm trying to filter a signal with a 10th order differential equation and for loop, with the following code, but i'm keep getting this error
Array indices must be positive integers or logical values.
Error in EOG (line 106)
new_data = data_h(k:-1:k-10);
can you please help me fix it , and tell me if it's a code or just syntax error?
TimeStamp = 0:T:59.99;
N = 10;
Fg = 1;
Wn = Fg/2;
aTP = fir1(N,Wn);
for k = 1:numel(data_h)
new_data = data_h(k:-1:k-10);
Y(k) = aTP.*new_data;
end
plot(TimeStamp,data_h,TimeStamp,Y)
legend("data_h","Y")

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采纳的回答

David Fletcher
David Fletcher 2021-5-2
On the first iteration of your loop the indexing expression will expand to
new_data = data_h([1 0 -1 -2 -3 -4 -5 -6 -7 -8 -9])
As the error says: you can't index with zero or negative values
  2 个评论
Abd Alsalam Al Saell
Abd Alsalam Al Saell 2021-5-3
first of all thanks!
but one more error -_-
--> Unable to perform assignment because the indices on the left side are not compatible with the
size of the right side.
Error in EOG (line 108)
Y(k) = aTP.*new_data';
.
.
.
n = 0;
for k = 1:numel(data_h)
n = n+11;
new_data = data_h(k:n);
Y(k) = aTP.*new_data';
end
.
.
.
David Fletcher
David Fletcher 2021-5-3
In this case the error is that you are trying to cram a vector into a single column. If you want to save the data from each iteration use:
Y(k,:) = aTP.*new_data';

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