0 个投票

clear all
close all
N=1001;
f1=1.0000e9;
f2=1.0200e9;
fs=4*f1;
w1=2*pi*f1/fs;
w2=2*pi*f2/fs;
n=0:N-1;
s1=sqrt(1.00)*exp(i*w1*n);
s2=sqrt(0.10)*exp(i*w2*n);
wn=sqrt(0.10)*(randn(1,N)+i*randn(1,N));
x=s1+s2+wn;
x=x(:);
f=0:fs/(N-1):fs;
FFT_abs=abs(fft(x));
plot(f,20*log10(FFT_abs/max(FFT_abs)),'linewidth',3,'b+-');
It gives this error:
Error using plot
Data must be a single matrix Y or a list of pairs X,Y.

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 采纳的回答

KSSV
KSSV 2021-5-3

0 个投票

Use:
plot(f,20*log10(FFT_abs/max(FFT_abs)),'color','b','linewidth',3);

更多回答（3 个）

Stephen23
Stephen23 2021-5-3
编辑：Stephen23 2021-5-3
Ran in:

0 个投票

Ran in:
Exactly as the plot documentation shows, the LineSpec must come directly after the X/Y data:
plot(f,20*log10(FFT_abs/max(FFT_abs)),'b+-','linewidth',3);
Walter Roberson
Walter Roberson 2021-5-3

0 个投票

plot(f,20*log10(FFT_abs/max(FFT_abs)),'b+-','linewidth',3);
Named options must always go after all positional parameters.
Mathieu NOE
Mathieu NOE 2021-5-3

0 个投票

hello
it works better this way :
plot(f,20*log10(FFT_abs/max(FFT_abs)),'b+-','linewidth',3);

5 个评论
显示 3更早的评论 隐藏 3更早的评论

Sadiq Akbar
Sadiq Akbar 2021-5-3
Thank you to all of you. But tell me which answer should I accept now as all have given me the correct asnwer?
Mathieu NOE
Mathieu NOE 2021-5-3
me, me, !! (I am not yet MVP !!!)
just kidding, pick the one you want . I am not in a beauty conquest
Mathieu NOE
Mathieu NOE 2021-5-3
what a success . 3 MVP answers for a plot command issue. Wow.
Sadiq Akbar
Sadiq Akbar 2021-5-3
My hear wants to accept all the answers but I think its not possible. Then logically speaking, first of all KSSV has given me the answer, so definitely he has more right though I used the command of Walter Roberson. However thanks to all of you for your prompt responses.
Walter Roberson
Walter Roberson 2021-5-4
KSSV's solution does not set the line style or the marker.

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