Hello Niklas,
To limit cars to using one charger at a time, introduce binary variables to indicate charger usage. Here's a streamlined approach:
- Binary Variables: Create y(i,j) to show if car i uses charger j.
- Constraints:
- Link x(i,j) (charging amount) to y(i,j) using a large constant (bigM): x(i,j) <= bigM * y(i,j).
- Ensure each car uses at most one charger: sum(y, 2) <= 1.
3. Objective: Maximize charging without changes.
charger = [11, 22, 50];
cars = [10, 20, 30, 40];
maxCurrentCar = [11, 22, 11, 22];
x = optimvar('x', length(cars), length(charger), 'LowerBound', 0);
y = optimvar('y', length(cars), length(charger), 'Type', 'integer', 'LowerBound', 0, 'UpperBound', 1);
bigM = max(charger);
prob = optimproblem;
prob.Objective = -sum(sum(x));
prob.Constraints.chargerconstr = sum(x, 1) <= charger;
prob.Constraints.carcapconstr = sum(x, 2) <= cars';
prob.Constraints.cartimeconstr = sum(x, 2) <= maxCurrentCar';
prob.Constraints.useChargerConstr = x <= bigM * y;
prob.Constraints.oneChargerPerCarConstr = sum(y, 2) <= 1;
opts = optimoptions('intlinprog', 'Display', 'off', 'PlotFcn', @optimplotmilp);
[sol, fval, exitflag, output] = solve(prob, 'options', opts);
disp(sol.x);
I hope it helps!
