Find index where condition is true, or end of matrix

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Bob Thompson
Bob Thompson 2021-5-5
回答： Bob Thompson 2021-5-5
I have an array that represents the time based states of an analysis. I want to search the array for where a certain state starts, and if the state doesn't exist, then pick the final index of the array.
statestart = find(Results.state==5,1); % Find index of first time state is 5
if isempty(statestart)
statestart = numel(Results.state);
end
I know this works, but I would like to know if it's possible to get the same result without an if statement.
  1 个评论
Mario Malic
Mario Malic 2021-5-5
编辑：Mario Malic 2021-5-5
Maybe you could create a vector that contains states that are within Results.state using unique, that way you could skip on checking for non-existant states.

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采纳的回答

Bob Thompson
Bob Thompson 2021-5-5
I appreciate the input, this is the best I was able to do:
statestart = [find(Results.state==5,1) numel(Results.state)];
statestart(1)

更多回答（1 个）

Jonas
Jonas 2021-5-5
you could set the last entry to the condition you are searching for and then use your find function. this way at least one index can be found where the condition is met
  1 个评论
Paul Hoffrichter
Paul Hoffrichter 2021-5-5
But how does the program know that this added last entry is phony data? An if-statement still appears to be required.

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