How to replace certain values in an array without using for-loop?

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Louis
Louis 2013-7-16
I have a very long array of length couple million. Say, A=[1;2;3;4;5;2;3;4;1;....] I have another array of different length (order of thousands to millions), we can call this second array B.
I would like to replace values in the first array with 0s if the value in A is present in B.
Currently, I have the following code to do it:
for i=1:length(B)
A(A==B(i))=0;
end
However, I would like to get rid of for loop and make this as efficient as possible since the arrays that I am working with is very large, and this is only a very small portion of the entire code, which needs to be computable before I graduate.
Thank you in advance,

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回答（1 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-7-16
编辑：Azzi Abdelmalek 2013-7-16
A(ismember(A,B))=0
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Image Analyst
Image Analyst 2013-7-16
No, it won't. That will work only if they match up. It won't remove elements that occur anywhere in A or B.

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