How to create a cell array with binary numbers?

Question

Nick 2021-5-6

0
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编辑： James Tursa 2021-5-6

I want to create a cell array 1000x11 of binary digits. I wrote the following code but when I run it, I get an array of {0×0 double} instead of {1x11}. What is wrong? How can I do that?

pop = cell(1000,11); 
for i = 1:1000  
  pop{i}=randi([0 1],1,11)
end

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Answer 1

James Tursa 2021-5-6

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编辑：James Tursa 2021-5-6

在 MATLAB Online 中打开

Your pop variable has 1000x11 = 11000 elements. Your for-loop only assigns values to 1000 of those elements (the first column). The rest are left as NULL which evaluates to 0x0 doubles. E.g., pop{i} = etc assigns that 1x11 array to a single element of pop, not spread out to 11 elements of pop.

If you want random 0 & 1 digits I would suggest you simply use a numeric or logical array instead of a cell array. E.g.,

pop = rand(1000,11) < 0.5;

Then to get at the binary digits you just need to access the rows of pop. E.g., pop(i,:) is the i'th row which contains the 11 binary digits.