reading a number from a string
显示 更早的评论
Hi all,
I've got a set of strings that are either [1x80] or [1x81], and I'm trying to parse an increasing number from the string. My problem occurs when the length of the string changes due to a number increment. A sample of the strings is:
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
str='(0020,0013) IS [99] # 2, 1 InstanceNumber'
str='(0020,0013) IS [100] # 2, 1 InstanceNumber'
str='(0020,0013) IS [101] # 2, 1 InstanceNumber'
I'd like to be able to parse the 98, 99, 100, 101 etc from the strings.
The format of the strings is identical, apart from the increasing number.
Currently I can use the following, which fails for the double digit numbers but works for the triple digits:
num=sscanf(str, '%*5c, %*10c %3s')
Any idea how I could make sure I always get the increasing number regardless of its length? It always starts at the same position and is contained in the square brackets.
Cheers, Jim
采纳的回答
Azzi Abdelmalek
2013-7-17
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
pattern='(?<=\[)\d+(?=\])'
out=regexp(str,pattern,'match')
更多回答（2 个）
Daniel Pereira
2013-7-17
x = sscanf(str,'(%d,%d) IS [%d] %s %d,%d %s');
num = x([1 2 3 5 6]);
when using
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
gives
20
13
98
2
1
and when using
str2='(0020,0013) IS [100] # 2, 1 InstanceNumber'
gives
20
13
100
2
1
hope it helps
Image Analyst
2013-7-17
Try this:
index = strfind(str, ']')-1
theNumber = str2double(str(17:index))
类别
在 帮助中心 和 File Exchange 中查找有关 Characters and Strings 的更多信息
2013-7-17
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
