reading a number from a string

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Jim O'Doherty
Jim O'Doherty 2013-7-17
Hi all,
I've got a set of strings that are either [1x80] or [1x81], and I'm trying to parse an increasing number from the string. My problem occurs when the length of the string changes due to a number increment. A sample of the strings is:
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
str='(0020,0013) IS [99] # 2, 1 InstanceNumber'
str='(0020,0013) IS [100] # 2, 1 InstanceNumber'
str='(0020,0013) IS [101] # 2, 1 InstanceNumber'
I'd like to be able to parse the 98, 99, 100, 101 etc from the strings.
The format of the strings is identical, apart from the increasing number.
Currently I can use the following, which fails for the double digit numbers but works for the triple digits:
num=sscanf(str, '%*5c, %*10c %3s')
Any idea how I could make sure I always get the increasing number regardless of its length? It always starts at the same position and is contained in the square brackets.
Cheers, Jim

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2013-7-17
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
pattern='(?<=\[)\d+(?=\])'
out=regexp(str,pattern,'match')
  1 个评论
Jim O'Doherty
Jim O'Doherty 2013-7-18
3 very good answers which all work perfectly for what I need
Thank you all very much!
Jim

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更多回答（2 个）

Daniel Pereira
Daniel Pereira 2013-7-17
x = sscanf(str,'(%d,%d) IS [%d] %s %d,%d %s');
num = x([1 2 3 5 6]);
when using
str='(0020,0013) IS [98] # 2, 1 InstanceNumber'
gives
20
13
98
2
1
and when using
str2='(0020,0013) IS [100] # 2, 1 InstanceNumber'
gives
20
13
100
2
1
hope it helps
Image Analyst
Image Analyst 2013-7-17
Try this:
index = strfind(str, ']')-1
theNumber = str2double(str(17:index))

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