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what is the problem in my following face recognition code?
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i dont know this is my code......
load data.mat
%Declare training data
P=[r h b bd];
%Create SOM neural network
%(64 minimum points and 64 maximum points)
net=newsom(minmax(P),[64 2]);
%Train SOM neural network for 1000 epochs
net.trainParam.epochs=100;
net=train(net,P);
%Plot SOM layer weights
x=net.iw{1,1},net.layers{1}.distances;
figure, plot(dist(x),'o');
title('SOM Layer Weights');
xlabel('Layer Weights');
ylabel('Magnitude');
%Plot SOM weight vectors
figure, plotsom(net.iw{1,1},net.layers{1}.distances)
sx=sim(net,P);
[l,m]=size(sx);
for u=1:1:m
sm(u)=find(sx(:,u));
end
%Load input face image
Q=imread('hulk6.jpg');
Q=double(reshape(Q,64,1));%(28 line)
i am getting the error
??? Error using ==> reshape
To RESHAPE the number of elements must not change.
Error in ==> simsom at 28
Q=double(reshape(Q,64,1));
what is the problem
5 个评论
omar shall
2014-1-16
Does this code compares a picture to pictures in database? if yes can you please add the edited file please
采纳的回答
the cyclist
2013-7-18
Line 28 of your code is attempting to reshape Q into a 64x1 vector. The error is saying that there are not 64 elements in Q, the operation is impossible. You could breakpoint your code at line 27 to see why Q doesn't have the number of elements you expect.
2 个评论
Matt Kindig
2013-7-18
Shot in the dark, but I think this should work:
Q = double(reshape(Q,64,[]));
Note that second parameter is empty ([]) rather than 1. Keep in mind this approach only works in the number of elements in Q (from the previous imread() call) is divisible by 64, i.e.,
numel(Q)/64
yields a whole number.
If that is not the case, you will also need to resample the image to a 64xN image using imresize() or similar. In that case, this should work:
Q = double(imresize(Q, [64 NaN]));
更多回答(1 个)
Image Analyst
2013-7-18
Q is an entire image. It probably has 10 or 20 megapixels in it. Why do you think it has only 64 pixels in it?
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