Trying to build an array of row vectors such that every possible combination of the 3 vector components is included

2 次查看(过去 30 天)
Take a vector [i j k]. I want to build an array of such vectors, with each element ranging from 1:20, such that every possible combination of the elements is included in the array. For example, the array would start with [1 1 1], [2 1 1], [3 1 1], and continue until [20 20 20] is reached. Here is what I have started with.
clear;
Ax_A = [];
for i = 1:20
Ax_A(i,1) = i;
end
for j = 1:20
Ax_A(:,2) = j
end
for k = 1:20
Ax_A(:,3) = k
end
When I don't supress the output for the 2nd (jth) and 3rd (kth) elements, it seems to be iterating through every single combination that I want. However, it is not storing all of these in the whole array that I am trying to build. If I do suppress the outputs, the result is just a 20x3 with i = 1-20, j = 20, and k = 20.

采纳的回答

David Fletcher
David Fletcher 2021-5-7
编辑:David Fletcher 2021-5-7
If you are going the loop route, then you want all three loops to be nested, rather than three separate loops. Something more like this:
clear;
Ax_A = [];
for i = 1:20
page=[];
for j = 1:20
for k = 1:20
page=[page; k j i];
end
end
Ax_A(:,:,i)=page;
end

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by