fill a matrix with binary code in a for loop
显示 更早的评论
Hi,
in a for-loop I get 30 times 3 bits each. To display the bits in a vector is no problem for me. But I would like to have a matrix after the 30 passes. Unfortunately my approach does not succeed.
for i = 1:30
% I reveive:
bit1 = [0]
bit2 = [1]
bit3 = [1]
% create Vektor works fine:
bitcode = [bit1 bit2 bit3]
% create Matrix doesnt work:
bitcode(i, :) = [bit1 bit2 bit3]
% neither that way:
for k = 1:length(bitcode)
bitcode(i,k) = bit(k)
end
end
Result should look like:
bitcode = [0 1 1; 1 1 1; 1 0 1]
I guess I'm doing something wrong?
3 个评论
David Fletcher
2021-5-9
编辑：David Fletcher
2021-5-9
I'm not sure how you expect to get a 3 row matrix when you are using a row indexing loop that iterates 30 times to create the matrix, nor am I sure how you expect each row to be different when it is based on the same arrangement of bits. However as a general example of using a loop to create a matrix, this might be of help:
code = [0 1 1]
for k = 1:length(bitcode)
bitcode(k,:) = code
end
David Fletcher
2021-5-10
Ok, I'll post it as an answer if it helped you, but it's not a big deal to me
采纳的回答
David Fletcher
2021-5-10
code = [0 1 1]
for k = 1:length(bitcode)
bitcode(k,:) = code
end
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Creating and Concatenating Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
