fill a matrix with binary code in a for loop

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Christian
Christian 2021-5-9
回答： David Fletcher 2021-5-10
Hi,
in a for-loop I get 30 times 3 bits each. To display the bits in a vector is no problem for me. But I would like to have a matrix after the 30 passes. Unfortunately my approach does not succeed.
for i = 1:30
% I reveive:
bit1 = [0]
bit2 = [1]
bit3 = [1]
% create Vektor works fine:
bitcode = [bit1 bit2 bit3]
% create Matrix doesnt work:
bitcode(i, :) = [bit1 bit2 bit3]
% neither that way:
for k = 1:length(bitcode)
bitcode(i,k) = bit(k)
end
end
Result should look like:
bitcode = [0 1 1; 1 1 1; 1 0 1]
I guess I'm doing something wrong?
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Christian
Christian 2021-5-10
编辑：Christian 2021-5-10
thank you! you are absolutely right. logic is sometimes not very strong with me. your solution works, thank you very much!:)
(@David Fletcher: I would like to confirm your statement as an answer, unfortunately I can't do that since you used the comment function)
David Fletcher
David Fletcher 2021-5-10
Ok, I'll post it as an answer if it helped you, but it's not a big deal to me

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采纳的回答

David Fletcher
David Fletcher 2021-5-10
code = [0 1 1]
for k = 1:length(bitcode)
bitcode(k,:) = code
end

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