Control Dynamically Multi-Dimension Matrix on fprintf

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Merih Dikbas
Merih Dikbas 2021-5-10
评论： Merih Dikbas 2021-5-10
Hi, I have 3x3x3 array and I can print elements on txt like this:
A(:,:,1)=[1 2 4 ; 5 2 1 ; 6 2 1];
A(:,:,2)=[4 6 1 ; 8 0 3 ; 1 2 4];
A(:,:,3)=[5 8 2 ; 4 4 4 ; 1 0 0];
function PrintArray(A)
MyText=fopen('Text1.txt','wt');
for i=1:size(A,1)
for j=1:size(A,2)
for k=1:size(A,3)
PrintedVal=A(i,j,k);
fprintf(MyText,'A(%d,%d,%d) = %d \n',i,j,k,PrintedVal) ;
end
end
end
fclose(MyText);
end
I am looking for a script that it will automatically detect the number of dimensions, will be able to perform in 2D or 4D.
Thanks for helping.

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采纳的回答

Stephen23
Stephen23 2021-5-10
编辑：Stephen23 2021-5-10
Ran in:
A(:,:,1) = [1,2,4;5,2,1;6,2,1];
A(:,:,2) = [4,6,1;8,0,3;1,2,4];
A(:,:,3) = [5,8,2;4,4,4;1,0,0];
D = ndims(A);
F = repmat(',%d',1,D);
F = sprintf('A(%s) = %%d\n',F(2:end));
C = cell(1,D);
for k = 1:numel(A)
[C{:}] = ind2sub(size(A),k);
fprintf(F,C{:},A(k))
end
A(1,1,1) = 1 A(2,1,1) = 5 A(3,1,1) = 6 A(1,2,1) = 2 A(2,2,1) = 2 A(3,2,1) = 2 A(1,3,1) = 4 A(2,3,1) = 1 A(3,3,1) = 1 A(1,1,2) = 4 A(2,1,2) = 8 A(3,1,2) = 1 A(1,2,2) = 6 A(2,2,2) = 0 A(3,2,2) = 2 A(1,3,2) = 1 A(2,3,2) = 3 A(3,3,2) = 4 A(1,1,3) = 5 A(2,1,3) = 4 A(3,1,3) = 1 A(1,2,3) = 8 A(2,2,3) = 4 A(3,2,3) = 0 A(1,3,3) = 2 A(2,3,3) = 4 A(3,3,3) = 0

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