Filling array with dec2hex() value
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Hello,
I have an issue with fill my matrix after the use of dec2hex() function.
As the first step, I allocate space for a three-column matrix. The next step is to generate a random number and delete the decimal part of the number. Which are saved to the first column of matrix. In the last step, I want to converse decimal value to hexadecimal value by dec2hex() function. The conversion to show me basic error: " Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2." Is the problem with the output of the dec2hex() function?
Could you help me with the issue?
%%allocation memory for matrix
for n=1:len
data_extend(n,1) = 0;
data_extend(n,2) = 0;
data_extend(n,3) = 0;
end
%randomize fill of data_extend array
a = 0;
b = 255;
for n=1:len
data_extend(n,1) = (b-a).*rand(1,1) + a; %%rand number from interval 0-255; a-b
data_extend(n,1) = floor(data_extend(n,1)); %%delete decimal
end
%%conversion decimal to hex
for n=1:len
data_extend(n,3) = dec2hex(data_extend(n,1));
end
采纳的回答
Observe that the output of dec2hex() is a character array:
x = 123
hx = dec2hex(x)
gives
x =
123
hx =
'7B'
So in this example, the input is scalar numeric, but the output is 1x2 char. Not only is the size mismatched, they aren't the same datatype. You'll have to come up with a different way of storing the output -- a cell array or something.
2 个评论
per isakson
2021-5-11
%% allocation memory for matrix
data_extend = zeros(len,3);
Robert Plsicik
2021-5-12
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