Segmenatation for an image.

1 次查看（过去 30 天）

显示更早的评论

mecheal 2013-7-22

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/82734-segmenatation-for-an-image

how can i segment and count the number of non overlapping blood cells in this image :

http://i39.tinypic.com/2nw0guw.gif

i need a code for doing this...

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

回答（2 个）

Image Analyst 2013-7-22

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/82734-segmenatation-for-an-image#answer_92395

First of all, look over my image segmentation demo. http://www.mathworks.com/matlabcentral/fileexchange/?term=authorid%3A31862 Then look at how I filter out coins based on size. You need to do the same thing. If they overlap the size will be a lot bigger than if they don't overlap. So you just need to tweak the area value in my code and it should work for you.

9 个评论
显示 7更早的评论隐藏 7更早的评论

mecheal 2013-7-23

great idea MR. matt ,, but i ran ur code , there was a small problem , u count a overlapped cells , i just want u to modify ur code to just count the UNOVERLAPPED CELLS ,,,WITH GREAT REGARDS,,,

Matt Kindig 2013-7-23

See my comment immediately above. In general, I think it will be easier to count all cells (overlapped and non-overlapped alike), and remove the overlapping ones.

To identify the overlapping ones, you can (as Image Analyst stated) use an area criterion, removing all identified cells that exceed some threshold area. In my code above, I showed you how to visualize the areas of the various regions. I'll let you implement the logic about how to identify the overlapping cells.

请先登录，再进行评论。