find all sequences between delimiters in an array
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Given a sequence of numbers and a start and an end delimiters, how to find the index (start and end) of all possible sequence of numbers between delimiters (sequences can be of any length). Example:
v = [1 1 0 2 0 2 1 2 1 1 1 0 2 1 2 0 0 1 1 1 1 1 1 2 1 0 ]
A list of non-overalpping sequences and their start and end index that begin with 2 and end with 0 would be:
[2 0]
[2 1 2 1 1 1 0]
[2 1 2 0]
[2 1 0]
I feel like this could be solved using regular expression.
采纳的回答
v = [1,1,0,2,0,2,1,2,1,1,1,0,2,1,2,0,0,1,1,1,1,1,1,2,1,0];
[begIdx,endIdx,~,match] = regexp(sprintf('%d',v),'2.*?0')
更多回答（1 个）
Jonas
2021-5-11
0 个投票
you could convert the array to a string or char array and then use extractBetween() which does what you want
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