Exponential asymptote

15 次查看(过去 30 天)
Pat
Pat 2011-5-26
Hi,
I used an exponential function to fit my data and I'd like to know where the function reaches a plateau. How do I calculate that?
Here's the function I used: y = a1+a2*exp(-a3*t)
I also tried a power function : y = a*b^t
Thanks in advance!
  2 个评论
Sean de Wolski
Sean de Wolski 2011-5-26
I'm excited to read John's response if he sees this.
Andrew Newell
Andrew Newell 2011-5-26
Google "identifying asymptotes"

请先登录,再进行评论。

采纳的回答

Walter Roberson
Walter Roberson 2011-5-26
a1+a2*exp(-a3*t) plateaus at the point where a2*exp(-a3*t) is less than eps(a1) . You can work backwards from there:
a2*exp(-a3*t) = eps(a1)
exp(-a3*t) = eps(a1)/a2
-a3*t = ln(eps(a1)/a2)
t = -ln(eps(a1)/a2)/a3
You might need to tweak this calculation if a1 or a2 are negative.
  1 个评论
Walter Roberson
Walter Roberson 2011-5-26
That is the time t at which the plateau is reached. If your maximum t for your data is less than that number, your function has not reached the plateau.
You would know if you had reached a plateau because all of the function values after that would be identical (to within round-off error)

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Interpolation 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by