Puzzler for a Monday

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the cyclist
the cyclist 2013-7-22
评论： David Young 2015-1-27
Given a cell array of strings
A = {'MATLAB','HURRAY','SPARKLY','KITTENS','FUN'};
and a particular string value
B = 'KITTENS';
ensure that B is the last element of the cell array. If it isn't, move it to the end of A.
You cannot assume that B appears at all (in which case return A unchanged), but you can assume B does not appear more than once.
[I have a solution, but I post this as a puzzle because I bet someone can find a slicker one.]

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回答（6 个）

Azzi Abdelmalek
Azzi Abdelmalek 2013-7-22
idx=strcmp(A,B)
out=[A(~idx) A(idx)]
the cyclist
the cyclist 2013-7-22
Here's mine:
[~,idx] = sort(ismember(A,B));
A = A(idx)
Sean de Wolski
Sean de Wolski 2013-7-22
idx = ismember(A,B);
C = cat(isrow(A)+1,A(~idx),A(idx))
  1 个评论
Evan
Evan 2013-7-22
Awesome. I especially like the "isrow" trick. I'll be remembering that one.

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Evan
Evan 2013-7-22
编辑：Evan 2013-7-22
Here's my solution. It's ugly, but I think it's fairly general. :P
function A = cell_shuffle(A)
idx = cellfun(@(x)isequal(B,x),A);
A = [A(~idx) A(idx)];
end
This would make for a nice CODY problem, by the way.
Abdullah Caliskan
Abdullah Caliskan 2015-1-27
k=ismember(A,B) A(k)='' if sum(k)==0 A=A; else A=[A B] end
David Young
David Young 2015-1-27
[~, idx] = ismember(B, A);
C = circshift(A, [0 -idx]);
  1 个评论
David Young
David Young 2015-1-27
Note: does not preserve the ordering of the other elements.

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