join numbers in vector
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I have a row vector with 7 numbers, e.g. 13 30 44 12 44 23 12. I want to join all these numbers into a single number, or 13304412442312. I have not been able to find a method to do this. Can anyone please suggest a method to do this without using a for loop.
采纳的回答
x=[13 30 44 12 44 23 12];
stringX=num2str(x);
stringX=stringX(stringX~=' '); % remove the space
x2=str2num(stringX);
3 个评论
dpb
2013-7-23
Can avoid the need to strip out spaces by using
sprintf('%d',x)
For the specific case x is 14 decimal digits and will fit into a double; add another and will need a longer mantissa or will lose precision.
>> v=[52 v]
v =
52 13 30 44 12 44 23 12 15
>> sscanf(sprintf('%d',v),'%li')==str2num(sprintf('%d',v))
ans =
0
>>
Hence my earlier suggestion to use %li and sscanf() to get a 64-bit integer.
kjetil87
2013-7-23
agreed , int64 is better.
dpb
2013-7-23
Gives more dynamic range than double at cost of less flexible to other operations. Of course, OP will eventually run out of range there, too, if continues to increase the size of the vector...
更多回答（2 个）
Azzi Abdelmalek
2013-7-23
编辑：Azzi Abdelmalek
2013-7-23
a=[13 30 44 12 44 23 12]
b=strrep(num2str(a),' ','')
% This is a string, if you to get a number
b=str2num(strrep(num2str(a),' ',''))
dpb
2013-7-23
>> sscanf(sprintf('%d',v),'%lu')
ans =
13304412442312
>> whos ans
Name Size Bytes Class Attributes
ans 1x1 8 uint64
>> sscanf(sprintf('%d',v),'%li')
ans =
13304412442312
>> whos ans
Name Size Bytes Class Attributes
ans 1x1 8 int64
>>
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